Calculating ln in radioactive decay

AI Thread Summary
Radioactive decay is described by the equation N = N0e^(-λt), where N is the count rate after time t, N0 is the initial count rate, and λ is the decay constant. The half-life of a radioactive isotope is calculated using the formula t1/2 = ln(2)/λ. To find ln(2), one can use a calculator, and the confusion arises when trying to relate time (t) and count rate (N) to the decay constant. For example, with a count rate of 82 in the first minute and a time of 10 minutes, the calculations require understanding how to manipulate the decay equation. Clarification on these calculations is essential for those studying physics within a biology degree.
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Homework Statement



Radioactive decay is:

N = N0e-λt

N can also be used to describe count rate after a time, (t) where N0 is intial count rate and λ is decay constant...

Half life, t1/2 od radioactive isotope is

t1/2 = 1n2
λ

The λ should be under the ln2 but it won't let me underneath

How do I calculate 1n??

For example if time (t) in minutes is 10 and Count rate in 1 minute (N) is 82 what is 1n

I don't understand at all? Any helps is grealty appreciated

Thanks

Homework Equations



As above

The Attempt at a Solution



I found ln on the calculator but confused how I get the answer from t as and n...

I am doing as biology degree but doing a physics module which I am struggling with
 
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The equation for decay is
N = N_0 \,e^{-\lambda t}.
To find the half-life, set N = N_0/2:
<br /> \begin{align}<br /> \frac{N_0}{2} &amp;= N_0 \,e^{-\lambda t} \\<br /> \frac{1}{2} &amp;= e^{-\lambda t}.<br /> \end{align}
Now you just solve for t:
<br /> \begin{align}<br /> \ln \frac{1}{2} &amp;= -\lambda t \\<br /> t &amp;= - \frac{1}{\lambda} \ln \frac{1}{2}.<br /> \end{align}
 
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