Calculating Magnetic Force & Accel. of an Electron in VT

AI Thread Summary
To calculate the magnetic force acting on an electron in Vermont, the dip angle of the Earth's magnetic field is 74 degrees, with a horizontal component of 0.16G. When the electron is shot vertically upward at a speed of 10^6 m/s, the magnetic force can be determined using the equation F = qv x B, where q is the charge of the electron and B is the magnetic field strength. The direction of the force will depend on the orientation of the velocity and magnetic field vectors. If the electron is shot horizontally northward, the calculations will need to be adjusted for the new direction of motion. The resulting force and acceleration can be computed accordingly.
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Homework Statement



In Vermont the dip angle for the Earth's magnetic field(the angle the field lines make with the horizontal) is 74 degree and the component of the field parallel to the Earth's surface is 0.16G. If an electron is shot with a speed 10^6 m/s vertically upward there, how large a force acts on the electron and what is the direction of the force? How large an acceleration will this force cause?

Repeat the problem if the electron is shot horizontally northward.

mass of electron = 9.1 x 10^(-31) kg and 1G=10^(-4)T

Homework Equations





The Attempt at a Solution



some hints to get me started. Thanks.
 
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Try using F = qv x B
 

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