Calculating Mass Density of a Steel Sphere | Help Needed!

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Homework Help Overview

The discussion revolves around calculating the mass density of a steel sphere, with specific values provided for mass and volume. The original poster presents a calculation that leads to a significantly erroneous percent error when comparing their result to the accepted density of steel.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants question the correctness of the units used in the density calculation and the accuracy of the volume derived from the diameter measurement. There is also discussion about the potential misinterpretation of the diameter measurement, suggesting it may have been in millimeters rather than centimeters.

Discussion Status

Participants are actively engaging with the original poster's calculations, offering insights into possible errors and encouraging a reevaluation of the diameter measurement. There is no explicit consensus yet, but the conversation is guiding the original poster towards reconsidering their approach.

Contextual Notes

The original poster mentions constraints related to their lab experiment and the tools used for measurement, indicating potential sources of error in their calculations.

derivethis
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Hi all! This is my first post here. I have a question regarding how to calculate the mass density of a steel sphere. Any help is much appreciated!

Homework Statement


The mass of the sphere is equal to 8.4 grams. The volume of the sphere is equal to 1060 cm^3.


Homework Equations


The mass was found during our lab experiment. The volume was calculated from the equation: V = (4/3) pi R^3. The diameter of the sphere was 12.65 cm. Therefore, I calculated the volume as follows: (4/3) pi (12.65/2)^3 = 1060 cm^3.


The Attempt at a Solution


Mass density is equal to mass/volume; therefore it should be 8.4g/1060cm^3 = 0.0079gm/cm^3. However, I'm also supposed to calculate the percent error for my lab report, and the "true" value for the mass density of steel is given as 7.9 gm/cm^3. Percent error is equal to (|Accepted - Measured|)/Accepted * 100, which, in this case, would be (|7.9 - 0.0079|)/7.9 * 100 = 99.9%. This gives me a percent error of almost 100%! What am I doing wrong in my calculations? Please help! Thank you!
 
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Are you sure you have your units right?

1 gram = 10^-3 kg. And 1 cm^3 = 10^-6 m^3.

so 1 g/cm^3 = 10^-3 / 10^-6 kg/m^3 = 10^3 kg/cm

so your 0.0079 g/cm^3 = 7.9 kg/m^3.
 
Your volume is about 1000 cm3, which is 1 liter. Does that sound right?
 
Thank you for your replies!

l'Hôpital: I think that I'm supposed to keep the units in grams/cm^3. I think my lab group and I must have made some sort of error in lab, which, of course, I can't correct now. We had to use a micrometer to determine the diameter of the steel sphere, and I just now realized that there's no way that the diameter of the sphere was 12.65 centimeters since the sphere was tiny and 1 inch = 2.54 cm. Hmm ... I wonder if it should be 12.65 mm instead. I believe that when we used the micrometer, we had to take it out to the number 10 mark in order for the sphere to fit inside. Does anyone know what this means? Thank you!
 
derivethis said:
Thank you for your replies!

l'Hôpital: I think that I'm supposed to keep the units in grams/cm^3. I think my lab group and I must have made some sort of error in lab, which, of course, I can't correct now. We had to use a micrometer to determine the diameter of the steel sphere, and I just now realized that there's no way that the diameter of the sphere was 12.65 centimeters since the sphere was tiny and 1 inch = 2.54 cm. Hmm ... I wonder if it should be 12.65 mm instead. I believe that when we used the micrometer, we had to take it out to the number 10 mark in order for the sphere to fit inside. Does anyone know what this means? Thank you!
That doesn't really tell us much unless we would have access to the same kind of micrometer you used.

There's a decent chance that your measurement of the diameter was off by a factor of 10 - that's a relatively common mistake to make. So it might have been 12.65mm. Based on your memory of what the sphere looked like, does 12.65mm seem like a reasonable value for its diameter? If so, try recalculating the density using that diameter and see what you get.
 

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