Calculating Mass from Force & Acceleration

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To calculate the mass of the fork from the applied force and acceleration, start with Newton's second law, which states that the net force equals mass times acceleration. The equation derived is 0.35 N - (m * 9.8 m/s²) = m * 0.15 m/s². Rearranging gives 0.35 = 9.95m, allowing for the mass (m) to be solved. After calculating m, convert the result from kilograms to grams for the final answer. This method effectively combines the concepts of force, gravity, and acceleration to find mass.
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Homework Statement


You apply a force of .35N up to lift a fork, the resulting acceleration is .15m/s2. What is the mass in grams.


Please help I don't know where to start with this simple question.
 
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Start with identifying the net force acting on it, and use Newton's 2nd law. Please show an attempt.
 
The net force would not be zero and I am only given the applied force. Without a mass I don't know how I can get the force of gravity.

So as far as I can tell I have .35 Fg = m .15m/s2
 
Let mass = m & use symbols where needed.

What does Newton's 2nd Law say?
 
0.35 Fg = m .15m/s2
0.35 - (m 9.8 m/s2) = m 0.15ms2

The second law says that if the net force is not zero there is an acceleration in the direction of the force.
 
You apply a force of 0.35 N upward.

If the mass of the for is m, what force is gravity exerting downward on the fork?

What is the net force being exerted upon the fork?
 
Wouldn't I need the mass of the fork (m) to calculate the force exerted by gravity?
 
You will have "m" in two places in your equation. Use algebra to solve for m.

I repeat:
What is the net force being exerted upon the fork?​
 
I can get up until
Fapp - m a(gravity) / a(applied) = m
Now I am a bit confused on my next move. Is this right so far? Since m on the left is being multiplied by the acceleration of gravity I think I should divide to get rid of it. But once I do the right side would cancel out to zero.
 
  • #10
Fapp - m g = m a

0.35 - m g = m (0.15)

Not sure what you use for g: 10 m/s2 or 9.8 m/s2 or 9.81 m/s2

Put in the appropriate number for g & solve for m.
 
  • #11
Yes, but as I said earlier I can get up until

0.35 - m g / 0.15 = m

I can't successfully eliminate the LH m. I tried dividing and adding it to the RH
 
  • #12
Before you divide by 'a', your correct equation, per post 5 2nd line, was

0.35 - (m 9.8 m/s2) = m 0.15ms2

leaving off units, then

0.35 - (9.8m) = 0.15m

Now this is algebra, add 9.8m to both sides

0.35 = 9.95m

Now solve for m and convert to grams.
 
  • #13
Thanks, that makes allot of sense.
 
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