Calculating Mass-Kepler's 3rd Law

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The discussion revolves around applying Kepler's 3rd Law to calculate mass, specifically using the formula a^3/p^2 = M. A user presents a calculation resulting in 3.6x10^11 MSun but is confused about the division step leading to 0.3550^12. Clarification is sought on whether the answer is in kilograms and if conversion to solar masses (MSun) is necessary. Participants engage in confirming the calculations and addressing the user's confusion. The conversation emphasizes understanding the relationship between the variables in Kepler's Law.
winterrose
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Okay, so I understand that a3/p2=M

I must be missing something though.

I know that (6x10^9)3 / (7.8x10^8)2 = 3.6x10^11 MSun

but I don't understand what step I'm missing. When I divide, I end up with 0.3550^12

what am I doing wrong?

Is my answer in kilograms, and do I have to convert it to MSun?
 
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winterrose said:
… = 3.6x10^11 MSun

but I don't understand what step I'm missing. When I divide, I end up with 0.3550^12

they're (aproximately) the same, aren't they? :wink:
 

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