Calculating Mass of Meteors After Impact

  • Thread starter Thread starter DerekP
  • Start date Start date
  • Tags Tags
    Impact Mass
Click For Summary

Homework Help Overview

The discussion revolves around calculating the mass of a meteorite that collides with Earth, given the force of impact and its acceleration. The subject area includes concepts from Newton's laws of motion, particularly focusing on the relationship between force, mass, and acceleration.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the application of Newton's second law and question which equation to use for calculating mass. There are discussions about the terms involved in the equation and what information is provided versus what is needed.

Discussion Status

Some participants have offered guidance on identifying the relevant equation and clarifying the relationships between the variables. There is an ongoing exploration of the problem setup, with various interpretations being discussed.

Contextual Notes

Participants note the potential for excess information in the problem statement and question the necessity of certain variables, such as the meteorite's speed, for solving the problem. The discussion also touches on the physical implications of the collision and the forces involved.

DerekP
Messages
5
Reaction score
0
3. Suppose a meteorite collides with Earth with a force of 6.41*1012N.

A. What is the mass of the meteorite if it's impact speed is 10 km/s so that it has an acceleration of approximatley -1.00*108 m/s2

I know I want to use an equation from Newton's second law but what equation do I use? and how to I change it so I can plug it in(if I need to)?

I figured out I want to use \sum_{\rm all}\bold{F}\,=\,m\frac{d(\bold{v})}{dt}\,=\,m \bold{a} (I believe) and I know I need these can anyone help me?

Acceleration = Net force divided by mass

Net force = rate of change of momentum

Net impulse = change of momentum
 
Last edited:
Physics news on Phys.org
Is there a chance that you have more info than needed? Which one of Newton's laws relates mass, force, and acceleration?
 
DerekP said:
3. Suppose a meteorite collides with Earth with a force of 6.41*1012N.

A. What is the mass of the meteorite if it's impact speed is 10 km/s so that it has an acceleration of approximatley -1.00*108 m/s2

I know I want to use an equation from Newton's second law but what equation do I use?
Newton's second law has only 1 equation. Look in your textbook.

and how to I change it so I can plug it in(if I need to)?

I figured out I want to use \sum_{\rm all}\bold{F}\,=\,m\frac{d(\bold{v})}{dt}\,=\,m \bold{a} (I believe)
Yes, that equation is Newton's 2nd Law.

Of the various terms listed in the equation (F, m, a etc.), which ones are given in the problem statement? Which one are they asking for?
 
DerekP said:
3. Suppose a meteorite collides with Earth with a force of 6.41*1012N.

A. What is the mass of the meteorite if it's impact speed is 10 km/s so that it has an acceleration of approximatley -1.00*108 m/s2

I know I want to use an equation from Newton's second law but what equation do I use? and how to I change it so I can plug it in(if I need to)?

I figured out I want to use \sum_{\rm all}\bold{F}\,=\,m\frac{d(\bold{v})}{dt}\,=\,m \bold{a} (I believe) and I know I need these can anyone help me?

Acceleration = Net force divided by mass

Net force = rate of change of momentum

Net impulse = change of momentum
Derek,

First draw a picture:

http://img709.imageshack.us/img709/7478/fma1.jpg

In this picture, the meteorite will apply an external force on the Earth (during the collision), pointing to the right. By Newton's 3rd postulate, the Earth will apply an equal and opposite force on the meteorite to the left. But this makes physical sense, since the meteorite will slow down, and come to rest, so its acceleration vector must point in the opposite direction of its velocity vector.

Isolate the meteorite (in the dashed line circle), and apply Newton's 2nd postulate. As others were pointing out, in this thread, you don't need to know the meteorite's speed to answer the question posed. Hope this helps.If we zoom in on the collision, which lasts \Delta t you'll see that a distance is required to bring the meteorite to rest. So there's going to be a crater. Hopefully, it's a small crater!

http://img693.imageshack.us/img693/7120/fma2z.jpg
 
Last edited by a moderator:

Similar threads

Replies
1
Views
2K
Replies
17
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
38
Views
4K
  • · Replies 30 ·
2
Replies
30
Views
4K
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
33
Views
4K
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K