Calculating max. kinetic energy (photoelectric)

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Homework Help Overview

The discussion revolves around calculating the maximum kinetic energy of electrons ejected from a photoelectric surface, given a cutoff potential and wavelength. Participants are exploring the relationship between energy, work function, and the photoelectric effect.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to calculate maximum kinetic energy using the cutoff potential and wavelength, questioning the validity of their methods and results. Some are exploring how to graph kinetic energy against photon frequency and seeking additional points for the graph.

Discussion Status

There are multiple interpretations of the equations involved in the photoelectric effect. Some participants have provided guidance on using the photoelectric equation and calculating energy from wavelength, while others express confusion about the relationship between kinetic energy and work function.

Contextual Notes

Participants are limited to the information provided (wavelength and cutoff potential) and are questioning how to derive additional values or clarify concepts related to the work function and kinetic energy.

NATSALANE
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given the cutoff potential (0.25 V) and wavelength (578 nm), how do i find the maximum kinetic energy of the electrons ejected from photoelectrif surface, in both eV and J?

my guess is,
KE = e Vo
= (1.6 x 10-19) x (0.25 V)
= 4.0 x 10-20 J

but if i convert that to eV, i get the same value as the cutoff potential - that can't be right.

can someone help me?
 
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also, how do i graph the maximum kinetic energy-vs-frqeuency of photons graph? i only have one value of frequency and kinetic energy. i know that the slope must be the same as the value of plank's constant, but assuming i do not know the constant, how can i find more points on the line to connect?
 
According to the photoelectric equation,
Energy of light radiation = Kinetic Energy of photoelectron + Work function

Here, you are actually calculating the work function and thinking that it is the Kinetic Energy. Calculate the energy of the light radiation [hc/(wavelength)], where h is Planck's constant and c is the speed of light.

Then, subtract work function from the calculated energy to obtain the max. K.E. of the photoelectron.
 
Max K.E. = h(v-vo) = hv - Work function
where h is Planck's constant, v is frequency of radiation and vo is the cutoff frequency. As you have already calculated the work function, therefore you can create the graph (which will be a straight line).
 
alecsing said:
According to the photoelectric equation,
Energy of light radiation = Kinetic Energy of photoelectron + Work function

Here, you are actually calculating the work function and thinking that it is the Kinetic Energy. Calculate the energy of the light radiation [hc/(wavelength)], where h is Planck's constant and c is the speed of light.

Then, subtract work function from the calculated energy to obtain the max. K.E. of the photoelectron.



all i am given is the wavelength and cutoff potential, so in order to find the maximum kin energy, don't i use this equation: Kinetic energy = speed of electron * cutoff potential ?

how does that equate to work?
 
NATSALANE said:
all i am given is the wavelength and cutoff potential, so in order to find the maximum kin energy, don't i use this equation: Kinetic energy = speed of electron * cutoff potential ?

how does that equate to work?

There is a previous thread:- https://www.physicsforums.com/archive/index.php/t-208429.html
. After viewing it, you will be able to understand the meaning of cutoff potential more clearly. It is used to calculate the work function and not the kinetic energy.
 
okay then.

so EK = (hc)/λ - eVo

i got the same answer as W but opposite sign (negative)...
 

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