Calculating max. kinetic energy (photoelectric)

AI Thread Summary
To calculate the maximum kinetic energy of electrons ejected from a photoelectric surface given a cutoff potential of 0.25 V and a wavelength of 578 nm, one must first determine the energy of the incident light using the equation E = hc/λ. The maximum kinetic energy can then be found using the formula KE = E - eVo, where eVo is the work function. The confusion arises from incorrectly equating the cutoff potential with kinetic energy. For graphing kinetic energy versus frequency, additional points can be derived by varying the wavelength and calculating corresponding energies.
NATSALANE
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given the cutoff potential (0.25 V) and wavelength (578 nm), how do i find the maximum kinetic energy of the electrons ejected from photoelectrif surface, in both eV and J?

my guess is,
KE = e Vo
= (1.6 x 10-19) x (0.25 V)
= 4.0 x 10-20 J

but if i convert that to eV, i get the same value as the cutoff potential - that can't be right.

can someone help me?
 
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also, how do i graph the maximum kinetic energy-vs-frqeuency of photons graph? i only have one value of frequency and kinetic energy. i know that the slope must be the same as the value of plank's constant, but assuming i do not know the constant, how can i find more points on the line to connect?
 
According to the photoelectric equation,
Energy of light radiation = Kinetic Energy of photoelectron + Work function

Here, you are actually calculating the work function and thinking that it is the Kinetic Energy. Calculate the energy of the light radiation [hc/(wavelength)], where h is Planck's constant and c is the speed of light.

Then, subtract work function from the calculated energy to obtain the max. K.E. of the photoelectron.
 
Max K.E. = h(v-vo) = hv - Work function
where h is Planck's constant, v is frequency of radiation and vo is the cutoff frequency. As you have already calculated the work function, therefore you can create the graph (which will be a straight line).
 
alecsing said:
According to the photoelectric equation,
Energy of light radiation = Kinetic Energy of photoelectron + Work function

Here, you are actually calculating the work function and thinking that it is the Kinetic Energy. Calculate the energy of the light radiation [hc/(wavelength)], where h is Planck's constant and c is the speed of light.

Then, subtract work function from the calculated energy to obtain the max. K.E. of the photoelectron.



all i am given is the wavelength and cutoff potential, so in order to find the maximum kin energy, don't i use this equation: Kinetic energy = speed of electron * cutoff potential ?

how does that equate to work?
 
NATSALANE said:
all i am given is the wavelength and cutoff potential, so in order to find the maximum kin energy, don't i use this equation: Kinetic energy = speed of electron * cutoff potential ?

how does that equate to work?

There is a previous thread:- https://www.physicsforums.com/archive/index.php/t-208429.html
. After viewing it, you will be able to understand the meaning of cutoff potential more clearly. It is used to calculate the work function and not the kinetic energy.
 
okay then.

so EK = (hc)/λ - eVo

i got the same answer as W but opposite sign (negative)...
 
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