Calculating Mechanical Energy Change of 1100kg Car

AI Thread Summary
The discussion centers on calculating the total change in mechanical energy for a 1100 kg car descending a hill. The formulas for kinetic energy (KE) and potential energy (PEg) were applied, resulting in KE of 220,000 J and PEg of 1,300,000 J, totaling 1,510,000 J or 1.51 MJ. However, the calculation is incorrect because the kinetic energy at the bottom already accounts for the potential energy lost during the descent. The focus should be on the change in mechanical energy, which indicates that the car loses potential energy while gaining kinetic energy. Ultimately, the correct approach is to consider only the change in kinetic energy for the final answer.
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1. A 1100 kg car at rest at the top of a hill accelerates down the road, reaching a speed of 20 m/s after descending a height of 120 m. What was its total change in mechanical energy (KE plus PEG) as of that moment in Megajoules?



2.KE = 1/2 mv^2 and PEg = mgh



3. I used the above formulas to figure out KE = 2.20E5 and PEg = 1.3E6. When I add both together, I get 1.51E6 and convert it to MJ = 1.51MJ. When I put in the answer, this is incorrect. Am I missing something?
 
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uno said:
1. A 1100 kg car at rest at the top of a hill accelerates down the road, reaching a speed of 20 m/s after descending a height of 120 m. What was its total change in mechanical energy (KE plus PEG) as of that moment in Megajoules?

2.KE = 1/2 mv^2 and PEg = mgh

3. I used the above formulas to figure out KE = 2.20E5 and PEg = 1.3E6. When I add both together, I get 1.51E6 and convert it to MJ = 1.51MJ. When I put in the answer, this is incorrect. Am I missing something?

The KE at the bottom of the hill already includes the m*g*h from the descent. You probably want to just use the KE as the answer.
 
It starts high and ends low, so it LOSES potential energy. It starts at rest and finishes in motion, so it gains kinetic energy. (I think)
 
kraus is right: so how much mechanical energy does the car lose?
 
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