Calculating Molecules in Moles of Oxygen?

  • Thread starter Thread starter cobrastrike
  • Start date Start date
  • Tags Tags
    Moles
AI Thread Summary
To calculate the number of molecules in 23 moles of oxygen, use Avogadro's number, which states that 1 mole equals 6.022 x 10^23 molecules. Therefore, multiplying 23 moles by Avogadro's number results in approximately 1.384 x 10^24 molecules of oxygen. The user expresses confusion about this calculation compared to other mole conversions, indicating a need for clarification. Understanding the mole-to-molecule conversion is essential for accurate chemical calculations. The discussion emphasizes the importance of Avogadro's number in determining the number of molecules in a given amount of substance.
cobrastrike
Messages
10
Reaction score
0
How many molecules are in 23 moles of oxygen?

I don't get it, I know how to do other kinds like How many moles are there in 25 grams of water? and How many grams are in 4.5 moles of Li20? but I don't get it.

THANK YOU in advance
 
Physics news on Phys.org
I believe the conversion is:

1 mole=6.022 x 10^23 molecules
 
Thank you
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top