Calculating Moment about a Point: Understanding FDCsin and FDCcos

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The discussion focuses on the calculation of moments about a point, specifically questioning the use of FDC(sin18.43)(9) in the moment equation. There is confusion regarding whether FDC(cos18.43)(3) is the correct representation, as the perpendicular distance from point D to the force FDC is highlighted. Participants also raise concerns about the omission of the 2kN force at point B, which could contribute to the moment about point I. The accuracy of the original author's calculations and assumptions is under scrutiny. Clarification on these points is necessary for a complete understanding of the moment calculations involved.
chetzread
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1. The problem sttatement, all variables and given/known data
i don't understand the moment FDC(sin18.43)(9) , I think it's wrong..
http://imgur.com/a/qPdqf

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The Attempt at a Solution


I think it should be FDC(cos18.43)(3), am i right?
the r is the perpedicular distance from D to force FDC, i have circled it...
Or I'm wrong? FDCsin18.43)(9) represent other moment?
 
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sorry, photo here
 

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there' also moment caused by other forces such as 2KN at B , why didnt the author consider that? the 2kN force can cause moment about I ,right?
 
is the author wrong ?
 

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