Calculating Normal and Frictional Forces on a Parked Car on an Inclined Road

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To calculate the normal and static frictional forces on a parked car on an inclined road, one must consider the car's weight and the angle of inclination. The normal force is not simply the mass times gravity; it requires resolving the weight into components parallel and perpendicular to the incline. The perpendicular component determines the normal force, while the parallel component relates to the static frictional force. Visual aids, such as diagrams, can assist in understanding the force distribution. Properly applying these principles allows for accurate calculations of the forces acting on the car.
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1. A car (m = 1940 kg) is parked on a road that rises 14.4 ° above the horizontal. What are the magnitudes of (a) the normal force and (b) the static frictional force that the ground exerts on the tires?



Homework Equations





3. I am not sure what I need to do here. Wouldn't the normal force just be the mass times gravity? Not sure what equations I should be using or how I should be incorporating the angle.
 
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luap12 said:
1. A car (m = 1940 kg) is parked on a road that rises 14.4 ° above the horizontal. What are the magnitudes of (a) the normal force and (b) the static frictional force that the ground exerts on the tires?



Homework Equations





3. I am not sure what I need to do here. Wouldn't the normal force just be the mass times gravity? Not sure what equations I should be using or how I should be incorporating the angle.

The normal force is the force exerted perpendicularly from the road on the car. You have to split the force of weight into one force that is pulling the object down the road at 14.4 degrees and one force perpendicular to the road. This image from SparkNotes could help you visualize the forces.
normal.gif
 
that works and makes sense now! Thanks!
 

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