Calculating Peak Velocity of a Magnet Under Continuous Magnetic Force

AI Thread Summary
To calculate the peak velocity of the magnet MagX under the influence of a constant magnetic force from MagY, the force in PSI can be converted to pounds by multiplying it by the area of contact. Using the conservation of energy principle, the work done on MagX can be expressed as the product of force and distance, equating it to the change in kinetic energy. The formula Fd = ½mv² allows for solving the peak velocity, where m is the mass of MagX. The initial kinetic energy is assumed to be zero, simplifying the calculation. This approach provides a clear method to determine the peak velocity of MagX.
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Homework Statement


Imagine you have a magnet (Henceforth named MagX) which weighs .03lbs, and it is being continuously pushed by another magnet's polar likes (Henceforth named MagY) with a force of 3 PSI. Is it possible to find the peak velocity of MagX, assuming that MagY stays at a constant distance of 0.5" away from MagX?

Friction is not factored in.
The dimensions of MagX are 2.0" x 0.5" x .125"

This isn't for "Homework", but it's relevant to a project which I cannot elaborate on.
I apologize if the question doesn't make sense or is too vague. I admit that I am no physics major and I honestly have no idea where to go from here.

Thank you for your time.
Wyatt
 
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Since you know the force in psi, you can convert that into a force (in lbs) by multiplying by the area and then apply conservation of energy.

force*distance = change in kinetic energy of magX (assuming 0 initial KE)

Fd = ½mv2

v would give the velocity in some units which I am not sure of since I never really used those units.
 
That's exactly what I needed to know. Thank you so much for the help rock.freak!
 
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