Calculating Photon Energy Needed to Exceed Fused Silica Glass Band Gap

AI Thread Summary
Fused silica glass is transparent to visible light but can absorb light at high intensities through multiphoton absorption. This process allows multiple photons to be absorbed simultaneously, which can help bridge the band gap of the material. For fused silica with a band gap of 4eV, two photons with 2eV energy each can be absorbed through two-photon absorption. The discussion also touches on the calculation of photon energy using the formula E = hc/λ, but there is confusion about how to apply it to find the minimum number of photons needed. Ultimately, the original poster resolved their query regarding the calculations.
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Glass is transparent to visibile light under normal conditions; however, at extremely high intensities, glass will absorb most of the light incident upon it. This works through a process known as multiphoton absorption. In this process, several photons are absorbed at the same time. If very intense light whose photons carry 2eV of energy is shined onto a material with a band gap of 4eV, that light can be absorbed through two-photon absorption, because two photons have the right amount of energy to bridge the band gap. What is the minimum number of photons of 800nm- light that are needed to equal or exceed the band gap of fused silica glass?

I tried Energy of photon= hc/\lambda... but then after that i don't know what to do. ... i know that energy is the J/ photon... so i multiply it by the energy in the band.,... but didnt get it! anyone knows how to do it?!
 
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never mind i got it..
 

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