Calculating Power of Pump in Flooded Basement

  • Thread starter Thread starter duke_nemmerle
  • Start date Start date
  • Tags Tags
    Power Pump
AI Thread Summary
To calculate the power of the pump in a flooded basement, the equation P = Δm/Δt (gh + 1/2v²) is utilized, where g is the gravitational constant, h is the height of the waterline, and v is the velocity of the water. A question arises regarding the use of the formula P = FΔd/Δt, as the force is assumed constant. However, it is clarified that the force cannot be determined without applying Bernoulli's equation, which accounts for fluid dynamics. The discussion highlights the importance of using appropriate equations for dynamic versus static fluids. Ultimately, the user plans to verify if both methods yield consistent results.
duke_nemmerle
Messages
50
Reaction score
1

Homework Statement


Water is pumped steadily out of a flooded basement at a speed of 5.0 m/s through a uniform hose of radius 1.0 cm. The hose passes out through a window 3.0m above the waterline. What is the power of the pump?


Homework Equations





The Attempt at a Solution



I actually correctly solved the problem by taking advantage of the fact that
P = \frac{\Delta W}{\Delta t } which for us is P = \frac{\Delta m}{\Delta t} (gh + \frac{1}{2}v^{2})

My question is, if the force applied is constant, why can't I use P = \frac{F\Delta d}{\Delta t} since it's a simple matter of finding the force and \frac{\Delta d}{\Delta t} = v is given.
 
Physics news on Phys.org
hello duke, i think the force F you specify cannot be found without using Bernoulli equation. :smile:
 
Yeah, I had actually found the force using an equation that is only good for static fluids, I'm going to see if using Bernoulli gets me the same result both ways. Thanks :)
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top