Calculating Pressure Drop in a Bronchial Constriction

frenchy7322
Messages
6
Reaction score
0
Q: When a person inhales, air moves down the bronchus (windpipe) at 15 cm/s. The average flow speed doubles through a constriction in the bronchus. Assuming incrompressible flow, determine the pressure drop in the constriction.

OK what confuses me is that I thought that if you decrease the width of a passage (e.g cholesterol in an artery) you increase pressure. However this asks for pressure DROP in constriction?:confused:

Equation I thought would be P = F/A, but not real sure at all.

Please help me get the ball rolling!
 
Physics news on Phys.org
To help you judge, let's compare this.
When there is a constriction in a pipe, the overall pressure in the WHOLE tube should be higher than that of a pipe with no constriction, given similar inlet flow speed. Now look at the tube with constriction, and compare the pressure at the inlet and at the constriction, the pressure at the constriction is always lower. It is this pressure difference that drives the air from inlet to the constriction! That phenomena is governed by the Bernoulli equation.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top