Calculating Pressure from Stacked Bricks: Fluids Homework Solution

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SUMMARY

The discussion focuses on calculating the minimum number of stacked bricks required to exert a pressure of at least one atmosphere on the ground. A single brick weighs 15.0 N with dimensions of 0.203 m x 0.0890 m x 0.0570 m. The pressure exerted is calculated using the formula pressure = force / area, where the area is determined by the face of the brick in contact with the ground. The correct approach involves maximizing pressure by minimizing the contact area, which was not initially applied in the user's calculations.

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  • Understanding of pressure calculations in physics
  • Familiarity with the concept of force and weight
  • Knowledge of basic geometry for area calculations
  • Awareness of atmospheric pressure standards (1 atm = 101300 Pa)
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  • Review the principles of pressure and force in fluid mechanics
  • Learn about the relationship between weight, area, and pressure in practical applications
  • Explore the concept of pressure distribution in stacked objects
  • Investigate how to calculate pressure using different orientations of objects
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This discussion is beneficial for physics students, educators, and anyone interested in understanding pressure calculations related to solid objects, particularly in the context of fluid mechanics and structural analysis.

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Homework Statement


A brick weighs 15.0 N and is resting on the ground. Its dimensions are 0.203 m 0.0890 m 0.0570 m. A number of the bricks are then stacked on top of this one. What is the smallest number of whole bricks (including the one on the ground) that could be used, so that their weight creates a pressure of at least one atmosphere on the ground beneath the first brick? (Hint: First decide which face of the brick is in contact with the ground.)

pressure = force / area
density = Mass / volume
1atm = 101300 Pa
Volume = l* w* h





The Attempt at a Solution


well what i did was i found the area of the face to be .203 * .0890..then i divided 15/ Area to get pressure then i did 101300 / pressure to get number of bricks..this doesn't work
 
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To get max pressure, the area should be the least. Do you think you have found that correctly?

After that, total weight/area = pressure on the ground.
 

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