Calculating Proton Speed in 0.1T Magnetic Field

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To calculate the speed of a proton in a 0.1T magnetic field, one must consider the magnetic force acting on the moving charge. The magnetic force can be expressed using the equation F = qvB, where q is the charge of the proton, v is its speed, and B is the magnetic field strength. Since the proton moves in a circular path, the centripetal acceleration is given by A = v²/r. Applying Newton's second law, F = ma, allows for the integration of these concepts to find the proton's speed. Ultimately, the solution involves combining these equations to derive the required speed of the proton in the beam.
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Homework Statement



A magnetic field of 0.1T forces a proton beam of 1.5mA to move in a circle of radius 0.1m. The plane of the circle is perpendicular to the magnetic field. What is the speed of the proton in the beam as it moves in the circle.

Homework Equations





The Attempt at a Solution


Not sure where to start
 
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How do you find the magnetic force on a moving charge? If something moves in a circle, what's it's acceleration?
 
A= v2/r
I think
 
jbuck886 said:
A= v2/r
I think
Good. Find an expression for the magnetic force and apply Newton's 2nd law.
 

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