Calculating Rainfall: Solving a Physics Problem for a City Area | Help Needed

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To calculate the total rainfall for a city area, multiply the rainfall depth (1.1 cm) by the area of the city (5 km x 9 km) to find the volume in cubic centimeters. This volume can then be converted to mass using the fact that 1 cm³ of water equals 1 gram. The mass in kilograms can be converted to metric tons by dividing by 1,000. Finally, to find the volume in gallons, convert the total volume from cubic centimeters to gallons using the appropriate conversion factor. Understanding these relationships allows for accurate calculations of rainfall impact.
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Please help with this problem. I don't understand how you can know a quantity of rainfall over the given city area just by knowing 1.1 cm. The problem:
A heavy rainstorm dumps 1.1 cm of rain on a city 5 km wide and 9 km long in a 2-h period.

(a)How many metric tons (1 metric ton = 10^3 kg) of water fell on the city? (1 cm^3 of water has a mass of 1 gram = 10^-3 kg.)

(b)How many gallons of water was this?

For A, I know that if I can find kg of water, I can find metric tons easily enough. I could find kg by the 1cm=1g=10^-3kg, but I don't know how to find out how much rain was dropped on the city given the dimensions and 1.1 cm. How do you relate these two?

Thanks,

Wade
 
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wadesweatt said:
Please help with this problem. I don't understand how you can know a quantity of rainfall over the given city area just by knowing 1.1 cm.

The problem:
A heavy rainstorm dumps 1.1 cm of rain on a city 5 km wide and 9 km long in a 2-h period.

(a)How many metric tons (1 metric ton = 10^3 kg) of water fell on the city? (1 cm^3 of water has a mass of 1 gram = 10^3 kg.)

(b)How many gallons of water was this?

Welcome to PF.

Maybe ask yourself this question?
Depth of water times area is volume isn't it?

Looks like you have what you need.
 
so does this mean I should multiply 1.1 cm x 45 km? or should I convert 1.1 cm to 1.1x10^-5 km, and then multiply?

And then that quantity is my volume of rainfall (in km?)...which I can then relate to cm>grams>kg>metric tons.
 
ok i got it.

Thanks.
 
wadesweatt said:
ok i got it.

Thanks.

Yes you do have it.

Good luck.
 
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