Calculating Rate of Climb for Beech Bonanza V-Tailed Aircraft

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The discussion revolves around calculating the rate of climb for a Beech Bonanza V-tailed aircraft using the formula R/C = (excess power)/weight. The user initially calculated the power required for level cruise incorrectly, resulting in an excessively high number that led to confusion about excess power. The correct calculation for power required (PR) was clarified, revealing that it should be derived from thrust required multiplied by velocity, yielding 68.3 HP instead of the inflated figure. The misunderstanding stemmed from an incorrect unit conversion involving multiplying by 60, which was unnecessary. The conversation concludes with a resolution on how to properly apply the power relationship for accurate calculations.
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OK, I have a question regarding this homework that I have to complete about power and airspeed.

I have a beech bonanza v-tailed aircraft and I need to calculate rate of climb in ft/min with a True airspeed of 110 knots. (110 knots = 185.7 ft/s)

I am using R/C= (excess power)/weight My problem is that when I found the power required for level cruise at the same speed as above, I got a huge number because I did PR=Thrust required x Velocity (200.3 lbs x 185.7ft/s)

This going to give me a negative number for my excess power. The power plant is capable of 345 hp at sea level.

What am I doing wrong?
 
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I'm calculating only 67.6 HP for cruise. Where did your huge number come from?
 
I honestly don't know what I'm doing wrong. I used the equation I described above and multiplied by 60 in order to get ft lbs/min.

:confused:
 
PR = TV
PR = (200.3 Lb_f)(187.5 \frac{ft}{sec})
PR = 37556.3 \frac{ft*Lb_f}{sec}

Use the relationship that 1 HP = 550 \frac{ft Lbf}{sec}

That leaves PR = 68.3 HP

Why are you multiplying by 60?
 
oh ok...that makes total sense. I was multiplying by 60 to try and convert the units, but now I can see how to get the answer. I didn't use that relationship that you gave.

Thank you!
 
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