Calculating reactions at supports if one support is elevated

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SUMMARY

This discussion addresses the calculation of reactions at supports for a simply supported beam when one support is elevated. Specifically, it examines a scenario where Support A is 100mm higher than Support B, with a uniformly distributed load (UDL) of 22kN/m over a length of 2.5m. The reactions at the supports must still be calculated based on the principles of static equilibrium, ensuring that all forces and moments sum to zero. Additionally, it emphasizes that roller supports do not contribute any reaction force parallel to their direction of free motion.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of simply supported beam mechanics
  • Familiarity with uniformly distributed loads (UDL)
  • Concept of roller support reactions in structural analysis
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  • Study the calculation of reactions in elevated beam scenarios
  • Learn about the effects of distributed loads on beam reactions
  • Explore static equilibrium equations in structural engineering
  • Investigate the role of roller supports in reaction force analysis
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Civil engineers, structural analysts, and students studying mechanics of materials will benefit from this discussion, particularly those focused on beam analysis and support reactions.

HoBBLeCooKiE
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Hi guys!

How can one calculate your reactions at both ends of a simply supported beam if one reaction is higher than the other one?
Example: Support A (one end of the beam) is 100mm higher than Support B (other end) and there is a 22kN/m UDL distributed along the length of 2.5m
Does your reactions at the supports still act perpendicular or at an angle due to the elevation change of support A?
 
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Make sure all the forces add to zero, and all the moments add to zero. With that you should be able to confirm any possible answers.

Also make sure rollers supports aren't providing any component of their reaction force parallel to their direction of free motion.
 

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