Calculating Resistance of a Non-Metallic Pencil Lead | 390 Ohm Example

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The discussion focuses on calculating the resistance of a non-metallic pencil lead using the formula R = ρ x l / A, where ρ is resistivity, l is length, and A is cross-sectional area. The resistivity of the pencil lead is given as 4.0 x 10^-3 m, with a length of 0.15 m and a diameter of 1.40 x 10^-3 m, leading to a calculated resistance of 390 Ohm. Some participants question whether the equation applies only to resistance wire, but it is clarified that the formula is valid regardless of the material type. Concerns about the uniformity of resistors and potential air pockets are raised, but these do not invalidate the calculation for this specific example. The conversation emphasizes the straightforward nature of the resistance calculation despite initial confusion.
qim
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I have a question:

A pencil "lead" is made from non-metallic material which has a resistivity, at room temperature, of 4.0 x 10^-3 m.

A piece of this meterial has a length of 0.15 m and a diameter of 1.40 x 10^-3 m.

Show that the resitance of this specimen is 390 Ohm.

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Well I though of using R = rho x l / A

But then I read earlier that " by examining the dimensions of the resistor (assuming it is made from resistance wire instead of carbon as some are) we can also work out its resistance"

Does that mean that the question is a red herring, as the pencil lead is made from non metallic material?

Help...

Thanks

qim
 
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Other than the units being wrong for resistivity (they should be ohmsxlength, not just length) there is no "red-herring". It is just a simple multiplication.

Njorl
 
Thanks Njorl

But what am I to make of the statement that the equation should only work for resistors made of resistance wire?

That's the bit I could not understand.

Thanks

qim
 
I'm just guessing here:

Is it possible that they're covering themselves to take into account that typical resistors aren't uniform on the inside? IIRC, some are (deliberately) packed with small pockets of air.
 
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