Calculating Resistance of Resistor for 12V/10W Lamp & 24V Accumulator

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To operate a 12V/10W lamp connected to a 24V accumulator, a resistor must be added in series to drop the excess voltage. The required resistance of the lamp is calculated using the formula RL = V²/P, resulting in 14.4 Ohms. The current through the circuit is determined to be approximately 0.83 Amps. The total resistance needed for the circuit is calculated as RR = (24V / 0.83A) - 14.4 Ohms, yielding a value of 14.5 Ohms for the additional resistor. The calculations confirm the necessity of the resistor to ensure proper lamp operation.
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Homework Statement


A lamp is marked 12V/10W. the lamp is connected to 24V accumulator. in series with lamp you must then connect a resistor.
Calculate the resistance of the resistor.


Homework Equations





The Attempt at a Solution

 
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What quantity is the same throughout a series circuit?
Can you calculate the value of this quantity that the bulb requires?
 
to lamp to work properly 12V and current I (which is according to P=IV) has to be provided. So apart from this 12V the rest of the 12V of the supply has to be given to the resistor in series.Now you know the voltage across the resistor and the current (which is same I). Now it's simple:)
 
P=V2/RL
RL=V2/P = 122/10
RL= 14.4 Ohms.
we know that when connecting in series, I=IL=IR
and also V=VL+VR

VL = RL * IL
IL = 12/14.4 = 0.83Amps.
so, V=Req * I
Req = V/I
RL+RR = V/I
RR = V/I - RL
= (24/0.83) - 14.4
= 14.5 Ohms.

PLEASE TELL ME IF IT'S TRUE.
 
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