Calculating Simple Harmonic Motion Parameters for a 10.0kg Mass

AI Thread Summary
A 10.0kg mass in Simple Harmonic Motion has an amplitude of 8.0 cm and a maximum acceleration of 3.26 m/s². The period and maximum speed can be calculated using the relationship between acceleration, displacement, and angular frequency (ω), where ω = 2πf and T = 1/f. The total mechanical energy of the system is equivalent to the kinetic energy at the equilibrium position, while maximum acceleration occurs when the velocity is zero at the peak displacement. Understanding the SHM curve can aid in visualizing the motion and applying relevant equations effectively. The phase constant φ does not affect the calculations for period, speed, or energy.
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Homework Statement


A 10.0kg mass undergoes Simple Harmonic Motion with an amplitude of 8.0 cm, a maximum acceleration of magnitude 3.26 m/s^2, and an unknown phase constant φ. What is the period, max speed of the mass, the total mechanical energy of the system, and the magnitude of the force on the particle when it is at half of its maximum displacement?


Homework Equations


a=xm-w^2cos(wt+φ)


The Attempt at a Solution


3.26=8.0-w^2cos(wt+φ)
what do i use for the w?
How can we do this without a phase.
 
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phase doesn't matters, its just where you set 0 time. So you would start at some arbitrary location on the SHM curve.
Maximum velocity occurs at the eqbm position.
total energy is equivalent to kinetic energy at eqbm
maximum acceleration, instantaneous, occurs when v=0, aka all energy is potential at the peak of the SHM

and

try drawing the SHM curve, it helps to understand what is going on
 
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relevant equations
\omega = 2 \pi f
T = \frac{1}{f}
 
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