Calculating Slit Width Using Microwave Wavelength

Thread starter Funf
Start date May 11, 2010
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Microwave Slit Wavelength Width

AI Thread Summary

To calculate the slit width using a microwave wavelength of 2.80 cm and a half-width of 0.67 m for the central maximum, the problem involves understanding the relationship between the slit width and the diffraction pattern. The half-width represents half the distance to the first minimum, which is crucial for determining the slit width. The formula relating these variables incorporates the wavelength and the geometry of the setup. Solving this problem requires applying principles of wave optics, specifically diffraction through a single slit. The discussion emphasizes the importance of correctly interpreting the half-width in the context of the diffraction pattern.

May 11, 2010

Funf

Homework Statement
Microwaves of wavelength 2.80 cm fall on a slit and the central maximum at a distance of 1.0 m from the slit is found to have a half-width (i. e. distance from middle of central maximum to first minimum) of 0.67 m. Find the width of the slit.

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May 11, 2010

Alter Baron

Have you tried the problem yet?
Hint: Half width is half the distance between two maxima.

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