Calculating Speed: Solving a Physics Wave Question | Homework Help

  • Thread starter Thread starter roxxyroxx
  • Start date Start date
  • Tags Tags
    Physics Wave
AI Thread Summary
The problem involves a cyclist and a car approaching each other, with the car emitting a sound at 500 Hz, which the cyclist hears as 535 Hz. The correct approach to solve for their speeds requires using the general Doppler effect formula, as both the source and receiver are in motion. The attempted solution incorrectly applied a simplified formula, leading to an incorrect speed calculation of 22.4 m/s instead of the correct 11 m/s. By applying the appropriate Doppler formula, the velocities of both the cyclist and car can be accurately determined. The final result indicates their speed is approximately 11.6 m/s.
roxxyroxx
Messages
48
Reaction score
0

Homework Statement


a cyclist and a car are approaching each other at the same speed. the car makes a 500 Hz sound at 343 m/s. the cyclist hears the sound as 535 Hz. How fast are they moving?


Homework Equations



f2 = f1(v/v\pmvs)

The Attempt at a Solution


535 hz = 500 hz(343 m/s\div343 m/s-vs)
vs = 22.4 m/s

but the answer should be 11 m/s
HELP ??
 
Physics news on Phys.org
In this case, both the source and the receiver move, so u must use the general Dopple formula, not the specific formula for each case the source moves or the receiver moves.

f' = f.(V+Vr)/(V-Vs)

f': frequency received

f: frequency created.

V: speed of the wave (sound or light).

Vr: velocity of the receiver: positive if moving toward the source, otherwise it's negative.

Vs: velocity of the source: positive if moving toward the receiver, otherwise it's negative.

In this case, Vs=Vr, and they're both positive. U will get the result 11,6 m/s. Be happy :D
 
great thanks!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top