Calculating Spring Constant of Bungee Cord

AI Thread Summary
To calculate the spring constant of a bungee cord for a jumper with a mass of 77.0 kg, the period of oscillation is determined to be 6 seconds based on the jumper hitting the lowest point 8 times in 48 seconds. Using the equations F = -kx and T = 2π√(m/k), the spring constant (k) can be derived from the period equation. An initial calculation yielded a spring constant of 8.94, but verification of the calculations is necessary. Participants in the discussion encourage showing detailed calculations to confirm accuracy. The focus remains on ensuring correct application of the physics equations to arrive at the right spring constant.
HHippo
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Homework Statement


A bungee jumper with a mass of 77.0kg, jumps from a high bridge. He just touches the water in the river below and after reaching this lowest point, he oscillates up and down, hitting the lowest point another 8 times in 48.0 seconds. Calculate the spring constant of the bungee cord.

Homework Equations


F = -kx
T = 2π√(m/k)


The Attempt at a Solution


I thought the period was 6 (48/8) and then used those two equations to solve for k. Got 8.94 but I am not sure if I did it right...
 
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Hi HHippo, welcome to PH.
Will you please show your calculations?
 
You know the period and mass you can solve for the spring constant directly from the period equation. Check your math.
 
method seems correct show your calculations
 

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