Calculating Surface Shear Stress in a Boundary Layer with Given Velocity Profile

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Discussion Overview

The discussion revolves around calculating surface shear stress in a boundary layer given a specific velocity profile defined by a quadratic equation. Participants are working through a homework problem that involves determining the shear stress based on provided velocity measurements at different distances from the surface.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents the velocity profile as v = ay + by² and seeks to calculate surface shear stress using the equation τ = μ(du/dy).
  • Another participant attempts to calculate du/dy using differences in velocity and distance, arriving at a value of 0.36 N/m², but notes that the expected answer is 1.17 N/m².
  • A suggestion is made to solve for constants a and b using the velocity data, with a being identified as the shear rate at the wall.
  • One participant calculates a = 50000 and finds a corresponding shear stress of 0.9 N/m², expressing difficulty in progressing further.
  • Another participant claims to have calculated a = 65000/sec, indicating they have resolved their issue.
  • A new participant expresses a similar problem and requests assistance.

Areas of Agreement / Disagreement

There is no clear consensus on the correct values for a and b, nor on the resulting shear stress, as participants present differing calculations and results. The discussion remains unresolved with multiple competing views on the approach to the problem.

Contextual Notes

Participants have not fully detailed their assumptions or the steps taken in their calculations, leading to potential gaps in understanding the relationships between the variables involved.

Who May Find This Useful

Students or individuals interested in fluid dynamics, particularly those dealing with boundary layer theory and shear stress calculations.

exphaze
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Homework Statement


If the velocity v of the air in a boundary layer having a dynamic viscosity of
18x10-6 kg/ms is given in terms of the distance y from the surface by v = ay + by2

where a and b are constants, calculate the surface shear stress if at 1.5 mm from the surface the velocity is 75 m/s, and at 3.0 mm from the surface it is 105 m/s.

Homework Equations


τ = μ(du/dy)

The Attempt at a Solution

 
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What have you figured out so far?
 
Chestermiller said:
What have you figured out so far?
I have tried the differences of the velocities and distance (du/dy) . Then multiplied it by the dynamic viscosity which came out as 0.36 N/m^2 but the answer is apparently 1.17 N/m^2.
 
exphaze said:
I have tried the differences of the velocities and distance (du/dy) . Then multiplied it by the dynamic viscosity which came out as 0.36 N/m^2 but the answer is apparently 1.17 N/m^2.
You need to solve for a and b from the velocity data; a is the shear rate at the wall.
 
Chestermiller said:
You need to solve for a and b from the velocity data; a is the shear rate at the wall.
I have worked out a = 50000 and substituted to τ*shear rate =μ and this came out as 0.9 N/m^2. I am still stuck.
 
Last edited by a moderator:
exphaze said:
I have worked out a = 50000 and substituted to τ*shear rate =μ and this came out as 0.9 N/m^2. I am still stuck.
I get a = 65000/sec
 
Chestermiller said:
I get a = 65000/sec
I got it now, Thanks for the advice!
 
Hello
I have the same issue, but unfortunately I can't solve it.
any hind please?
 

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