Calculating T2(x) at -1 with Error Less than 1/80 for f(x)=1/1-2x

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i really need help with this prob f(x)=1/1-2x i have to calculate T2(x) at -1 on the interval -1.5,-1 with an error less than 1/80.
I got f"'=48/(1-2x)^4 and f"'(-1.5)=3/16 and i can't get the error at 1/80 . Thank you
 
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There are several methods to give an upper bound on the error. The one I would use requires the (n+1)th derivative at some point in the interval - take the point where the absolute value of the derivative has the largest value for an upper bound.

Does this help to fill the gaps in your answer?
 
yep, thank you
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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