Calculating Tangential Forces on Carbide Tips of Circular Saw

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The discussion focuses on calculating tangential forces on carbide tips of a circular saw, specifically addressing the saw's no-load speed of 4800 rev/min and its negligible power output due to the absence of work being done. When cutting lumber, the saw's speed decreases to 2400 rev/min, generating a power output of 1.9 hp. Participants seek guidance on how to calculate the tangential forces exerted by the wood on the carbide tips. Key concepts include the relationship between torque, angular velocity, and power, as well as the absence of angular acceleration at no-load speed. The thread emphasizes the importance of understanding rotational motion equations for solving the problem.
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Homework Statement



The carbide tips of the cutting teeth of a circular saw are 8.6cm from the axis of rotation.

The no-load speed of the saw, when it is not cutting anything, is 4800 rev/min. Why is its no-load power output negligible?

While the saw is cutting lumber, its angular speed slows to 2400rev/min and the power output is 1.9hp. What is the tangential force that the wood exerts on the carbide tips?





The Attempt at a Solution



Would part a be that it's like that because it's not producing any work, there is no friction or any force acting/slowing down the rev/min.?

How do I start part b?

Before: 4800 rev/min 0hp
After 2400 rev/min 1.9hp

How would I calculate the tangential forces.?

Please and thank you.
 
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The no-load speed of the saw, when it is not cutting anything, is 4800 rev/min. Why is its no-load power output negligible?
Well, at constant speed, it is accelerating, i.e. there is not angular acceleration.

See - http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html - for equations of rotational motion.

See the relationship between torque, angular velocity and power. For relationship between applied force on moment arm and torque, see -

http://hyperphysics.phy-astr.gsu.edu/hbase/torq2.html#tc
 
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