Calculating Tension in a Cord Attached to an Inclined Crate

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The discussion centers on calculating the tension in a cord attached to a crate sliding down an incline. The crate, with a mass of 2.00 kg, accelerates at 3.0 m/s² on a frictionless surface inclined at 27.5°. Participants confirm that the mass of the pulley does not need to be known to solve the problem and emphasize using Newton's second law to relate acceleration and tension. The equation T = mg - ma is referenced, along with the need to consider the angle of inclination in calculations. Ultimately, the tension can be determined using the provided values and equations.
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A wheel of radius R = 10.0 cm is mounted on a frictionless horizontal axis. A massless cord is wrapped around the wheel and attached to a 2.00-kg crate that slides on a frictionless surface inclined at an angle of 27.5° with the horizontal. The crate accelerates down the incline at 3.0 m/s2. What is the tension in the cord?

Is it possible to still work with this since there is no mass attached to the pulley? I'm pretty sure I need to use a moment of inertia equation to calculate the tension.
 
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Yes, you can do this without knowing the mass of the pulley.
 
How does this work? I'm having a few problems.
 
You've been given the acceleration of the crate. What's your equation relating the acceleration and tension of the crate (using Newton's second law)?
 
F=ma

Would I have to worry about the circle?
 
T=mg-ma

T=18.6*sin(27.5)-2*3
 
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