Calculating Tension in a Horizontal Clothesline with Vectors

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Mark Nussbaum
Moved from a technical forum, so homework template missing
For some reason I'm really struggling to get a correct answer on this problem

"A horizontal clothesline is tied between 2 poles, 20 meters apart.
When a mass of 3 kilograms is tied to the middle of the clothesline, it sags a distance of 4 meters.

What is the magnitude of the tension on the ends of the clothesline?"

Work:
Fg = 3kg*9.81m/s^2 = 29.43
found θ with arctan(4m/10m) = 21.8°
moving the origin onto the point on the forces I then used component tree to solve for the y-direction where
Ft*sin(21.8)+Ft*sin(21.8)-Fg=0,
and ignored x since they would cancel out.

the answer I got was Ft = 39.623N
when I work in reverse the magnitude gives me the correct #s and everything adds to 0.

It's been a long time since I've done this kind of physics so maybe I'm missing something dumb here. But I can't find it.
 
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Seems fine to me. Why do you think there is a problem?
 
It is an online problem so it gives feedback and apparently this is an incorrect answer.
 
Some automated answer checkers will be very particular about what type of answers they accept. Minor things such as the number of decimals, the value of g that you use, or rounding errors can play a role in this.
 
Thanks I got it apparently I had to use exactly 9.8 for gravity.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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