Calculating Tension in Cables for 17.0 kg Speaker

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To calculate the tension in the cables supporting a 17.0 kg speaker, one must consider the forces acting on the system. The tension forces in the cables can be resolved into horizontal and vertical components, where the horizontal components cancel each other out. The sum of the vertical components must equal the weight of the speaker (mg). The relationship between the angles formed by the cables and the ceiling is crucial, as the angle between the tension vectors is twice the angle theta. Understanding these components allows for the correct calculation of tension in each cable.
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A loudspeaker of mass 17.0 kg is suspended a distance of h = 1.80 m below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of l = 3.30 m.

What is the tension in each of the cables?

Tried mg sintheta^2+mgcostheat^2=c^2 but no dice.

Anyone know anything?

thanks
 
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The tension forces point along the wires. Call their magnitude T and split them into horizontal and vertical components. The horizontal components cancel and the sum of the vertical components should cancel the mg force on the speaker.
 
The two (similar in magnitude tensions) and the weight form a triangle. If theta is the angle between the cables and the ceiling then the angle between the two tension vectors in the triangle is two times theta.
 
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