Calculating Tension Ratios for Equilibrium of Identical Bodies

  • Thread starter Thread starter kastamonu
  • Start date Start date
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
5 replies · 2K views
kastamonu
Messages
6
Reaction score
0

Homework Statement



Identical K,L and M bodies with a weight of P are in equilibrium . If the tension in the rope S1 is T1 and S2 is T2, then what is the ratio T1/T2? (The picture is below)

Homework Equations


The Attempt at a Solution



T1 equals P. But I am stuck with T2. I cannot decide whether it is 2P or 3P. Do we have to add the weight of K to T2? If we add, it will be 3P.
 
Attachments
  • tara0001.jpg
    tara0001.jpg
    8.5 KB · Views: 493
Last edited by a moderator:
Physics news on Phys.org
S2 is the uppermost vertical string and so must support all of the weight. Its tension will be 3P.
 
Then the answer is 1/3.But according to my book the answer is 1/2.
 
the pulley is attached to a rigid support.T2 has a weight of 2P
 
Let us call A the node above K and B the node above L. Let us assume that the angle between a horizontal line and the rope connecting A to B is 45 degrees (without this value you cannot compute a solution). Then you only have to write the equilibrium conditions at nodes A (first) and B (second).
The ratio is 1/2.