Calculating the 46th Derivative of a Quotient Function

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Homework Statement


If f(x) =(x^46 + x^45 + 2)/(x + 1)
, calculate f(46)(3), the forty-sixth derivative of f(x) at x = 3. Express
your answer using factorial notation: n! = n (n 1) (n 2) 3 2 1.

Homework Equations


Quotient rule

The Attempt at a Solution


I have tried trying to find a pattern, I'm on the third derivative and it seems really complicated.
 
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Kingyou123 said:

Homework Statement


If f(x) =(x^46 + x^45 + 2)/(x + 1)
, calculate f(46)(3), the forty-sixth derivative of f(x) at x = 3. Express
your answer using factorial notation: n! = n (n 1) (n 2) 3 2 1.

Homework Equations


Quotient rule

The Attempt at a Solution


I have tried trying to find a pattern, I'm on the third derivative and it seems really complicated.
Have you thought about doing the division before taking the derivative? I don't think that starting off with the quotient rule is the way to go.
 
So I get x^45+0, would I just take the 46 derivative of this(which would be 0)?
 
Check your arithmetic. That quotient doesn't equal ##x^{45}##.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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