Calculating the Distance of a Ball Kicked Off a Cliff

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A ball weighing 5kg is kicked off a 20-meter cliff, and the goal is to calculate the distance it travels. The gravitational acceleration is 9.80 m/s², and the final velocity (v(f)) is calculated to be 10 m/s, while the initial velocity (v(i)) is 0 m/s. The time of flight is determined to be approximately 2.019 seconds. There is confusion regarding the impulse value of 50 kg m/s, as it was not mentioned in the problem statement. The discussion highlights the need for clarity on the impulse and its relevance to the problem.
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Homework Statement



A ball weighing 5kg is kicked off a cliff with the height of 20 meters.
What is the distance the ball travels?

Known:

g (gravity) =9.80
I (impulse) = 50kg m/s
m (mass) =5kg
h (height) =20m

Unknown:

d=?

Homework Equations



?

The Attempt at a Solution



Found the v(f) which is 10 m/s.
Found the v(i) which is 0 m/s.
 
Last edited:
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t = square root of 2*20/9.81

t= 2.019 seconds
 
RiversAlone said:

Homework Statement



A ball weighing 5kg is kicked off a cliff with the height of 20 meters.
What is the distance the ball travels?

Known:

g (gravity) =9.80
I (impulse) = 50kg m/s
m (mass) =5kg
h (height) =20m
How do you know the impulse is 50 kg m/s? The problem statement did not say anything about impulse.

Unknown:

d=?

Homework Equations



?

The Attempt at a Solution



Found the v(f) which is 10 m/s.
Found the v(i) which is 0 m/s.
How did you get these?
 

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