Calculating the Fall Time of a High Diver from 36 m

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To calculate the fall time of a high diver from 36 meters, the relevant kinematic equation is x = (1/2)at², where x is the distance fallen, a is the acceleration, and t is the time. Given that the diver falls from rest with an acceleration of 10 m/s², the equation can be rearranged to solve for time. Substituting the values, the time interval can be calculated. The final answer provides the duration of the dive, confirming the importance of using the correct kinematic equations in physics problems. Understanding these principles is crucial for solving similar motion-related queries.
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If a high diver plunges from 36m above the water, what is the length of the time interval during which the diver falls through the air? - assume that throughout their dive, the diver is falling vertically from rest with an acceleration of 10\ ms^{-2}
I'm not sure how to answer this. I think I'm missing something really basic here.

Thanks for your help.
 
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Could you list the equation(s) you think are relevant to this problem? Hint: kinematic equations.
 
Oh. I've got it now. x=\frac{at^2}{2}. I missed that one when I looked through my formulas.

Thanks
 
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