Calculating the Minimum Proton Speed Near a Lead Nucleus

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To calculate the minimum speed of a 20.0 MeV proton near a lead nucleus, one must first convert the energy from MeV to joules, using the conversion factor of 1 eV = 1.6 x 10^-19 Joules. The charge of the lead nucleus can be determined using the formula q = ne, where n is the number of protons (82 for lead) multiplied by the fundamental charge. It is essential to consider both the kinetic energy of the proton and the electric potential energy in the calculations. Relevant equations for kinetic and potential energy will be necessary to complete the analysis. Understanding these concepts is crucial for solving the problem effectively.
Gurneet
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1. Predict the minumum speed of a 20.0MeV proton as it passes within 1.0x10^-13 meters of a lead nucleus having 82 protons. (Note: 1eV = 1.6x10^-19 Joules)



2. How do I start off?



3. All i can think of is to get a charge for the lead nucleus by using q=ne which is the number of electrons/protons multiplied by the fundamental charge(1.6x10^-19) and also convert the MeV into joules using the note given at the end of the question.
 
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Gurneet said:
1. Predict the minumum speed of a 20.0MeV proton as it passes within 1.0x10^-13 meters of a lead nucleus having 82 protons. (Note: 1eV = 1.6x10^-19 Joules)

2. How do I start off?

3. All i can think of is to get a charge for the lead nucleus by using q=ne which is the number of electrons/protons multiplied by the fundamental charge(1.6x10^-19) and also convert the MeV into joules using the note given at the end of the question.
That's a start. Think in terms of the proton's kinetic energy and (electric) potential energy -- you'll need to look up the equations for those, if you don't know them.
 
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