Calculating the Speed of a Seagull Diving for Clams in 3.32 Seconds

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To calculate the speed of a seagull diving for clams, the problem involves a clam released from a height of 100 meters, hitting the beach in 3.32 seconds. The vertical component of velocity (vy) can be determined using kinematic equations, factoring in gravitational acceleration. Once vy is calculated, the horizontal component (vx) can be derived. The final speed of the seagull at the moment of release can be expressed as the product of vx and time. The calculations confirm the necessary components for determining the seagull's speed.
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1. A seagull diving towards a stone beach at an angle of 60 degrees to the vertical releases a clam from a height of 100 meters. The clam hits the beach 3.32 seconds later. To the nearest tenth of a m/s what was its speed when it was released?



2. v=v_0 + a*t
 
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If v is the velocity of seagull when it releases the clam, find the horizontal and vertical components of v.
Height is given, time is given and g is known.
Use the proper kinematic equation to find vy.
From that you can find vx.
required answer is vx*t.
 
rl.bhat said:
If v is the velocity of seagull when it releases the clam, find the horizontal and vertical components of v.
Height is given, time is given and g is known.
Use the proper kinematic equation to find vy.
From that you can find vx.
required answer is vx*t.

Thanks, I think that I got it now
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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