Calculating the tangential component of the force acting on a projectile

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SUMMARY

The discussion focuses on calculating the tangential component of the force acting on a projectile launched horizontally from a height. The relevant equations include Newton's second law, F = ma, and the velocities in both horizontal (V(h) = v(0)) and vertical (V(v) = mt) directions. The horizontal force component (F(h)) is zero due to negligible air resistance, while the vertical force component (F(v)) equals mg. The angle of the projectile's trajectory changes over time and can be determined using the horizontal and vertical velocity components.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Basic knowledge of projectile motion
  • Familiarity with horizontal and vertical velocity components
  • Concept of gravitational force (mg)
NEXT STEPS
  • Calculate the angle of trajectory using the relationship between horizontal and vertical velocities
  • Explore the effects of air resistance on projectile motion
  • Study the derivation of projectile motion equations
  • Investigate the impact of initial launch speed on projectile trajectory
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for examples of force calculations in real-world scenarios.

kylera
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Homework Statement


Consider a projectile launched horizontally out the window of a tall building at a speed v(0). Determine an expression for the tangential component of the force acting on the projectile in terms of m, g, t, and v(0). Assume that the air has a negligible effect on the motion.


Homework Equations


F = ma, mostly deductions.


The Attempt at a Solution


V(h) = the horizontal velocity = v(0)
V(v) = the vertical velocity = mt

From here, I assume that since the horizontal velocity does not change because of negligible air resistance, F(h) = horizontal element of the total force applied on the projectile = zero. F(v) = mass * gravity = mg. However, this brings me to where I'm stuck -- I can't figure out how to determine the angle at which the projectile is falling. It can't be straight down. Do I find the angle using the velocities instead and then apply it to the force?
 
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kylera said:
From here, I assume that since the horizontal velocity does not change because of negligible air resistance, F(h) = horizontal element of the total force applied on the projectile = zero. F(v) = mass * gravity = mg. However, this brings me to where I'm stuck -- I can't figure out how to determine the angle at which the projectile is falling. It can't be straight down. Do I find the angle using the velocities instead and then apply it to the force?

Hi kylera! :smile:

Yes, the angle changes with t …

so find the horizontal and vertical components of the velocity as a function of t. :smile:
 
Done! Thanks!
 

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