Calculating Time for Bus to Catch Anna - Motion Problem

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A cyclist named Anna travels at a constant speed of 12 m/s, while a stationary bus begins to accelerate uniformly at 1.5 m/s² as she passes. The problem involves calculating the time it takes for the bus to catch up to Anna. The relevant equations include the distance traveled by both Anna and the bus, leading to the equation 12t = 0.5 * 1.5 * t². After simplifying, the quadratic equation 1.5t² - 12t - 48 = 0 is derived, with the correct positive solution for time being 16 seconds. The discussion emphasizes understanding the kinematic equations and the relationship between acceleration, time, and displacement.
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A cyclist, Anna is traveling at a constant speed of 12m/s when she passes a stationary bus. The bus starts moving just as Anna passes, and it accelerates uniformaly at 1.5m/s.

How long does the bus take to catch Anna??
 
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Write down the relevant equations. Show your attempts.
 
alright this is what i did but i didnt get the correct answer.

equation formed
12t=0.5*8*12 + 1.5t(t-8)

simplify it down and i got 1.5t^2-12t-48=0, t>0 is 10.9

answer is suppose to be 16
 
Bus starts from rest. So in time t the distance moved by the bus is 1/2*a*t^2. During that time distance moved by the cyclist is v*t. If the meet after this time, these distances must be equal.
 
is a the acceleration? and why is it t^2?

if you can, can you show me your full working out
 
Yes. a is the acceleration. What is the kinematic equation which contains initial velocity, acceleration, time and displacement? And unit of acceleration is m/s^2
 
ohhhhhhhhhhhhhhh...thnx i get it now. I am suppose to use x=ut+1/at^2 formula
 
Yes.
 
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