Calculating Torque for F1: 50N at d1-d3

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Homework Help Overview

The problem involves calculating torque in a scenario where a force of 50N is applied, with specific distances (d1, d2, d3) provided. The original poster seeks clarification on how to apply the torque equation given that the force is not at the center of gravity.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants question the location of the pivot point and the significance of the distances provided. There is a discussion about the applicability of the torque equation when the force is not applied at the center of gravity. Some participants also explore the concept of moments and torque being zero when the force's line of action passes through the pivot point.

Discussion Status

The discussion is ongoing, with participants providing feedback on attempts and seeking further clarification on torque concepts. Some guidance has been offered regarding the relationship between force direction and torque, but no consensus has been reached on the calculations.

Contextual Notes

There are requests for additional information, such as the location of point 'a' and a diagram to clarify the setup. The original poster expresses uncertainty about their understanding of the material.

cdornz
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Homework Statement


What is the torque about a?
F1 = 50N (located between d2 and d3)
d1 = 9cm
d2 = 10cm
d3 = 8 cm


Homework Equations


T=(F)(Lever Arm)


The Attempt at a Solution


I'm extremely rusty with this material, but I realize I can't quite use the torque equation since the force isn't at the center of gravity. Any help would be appreciated.
 
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Please provide a complete description of the problem. Where's a? What are d1, d2, and d3? A diagram would help.
 
This is what I worked it out to be, just want to make sure I'm doing it right.
 

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cdornz said:
This is what I worked it out to be, just want to make sure I'm doing it right.
Looks good to me.
 
thank you! and just one more question - slightly related to torque equations in general. When the force is exerted in that direction, it is considered a moment and therefore equal to 0 correct? Because no actual force is exerted on that line? So I would then think that the torque about p would be zero.
 

Attachments

  • 973349_10151935821238056_437964306_n.jpg
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cdornz said:
thank you! and just one more question - slightly related to torque equations in general. When the force is exerted in that direction, it is considered a moment and therefore equal to 0 correct? Because no actual force is exerted on that line? So I would then think that the torque about p would be zero.
The lever arm is the perpendicular distance from the pivot point to the line of action of the force. In this case, the line of action of the force passes through p, so the lever arm and thus the torque is zero. Force is exerted, of course, but no torque.
 

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