Calculating Torque to Accelerate

AI Thread Summary
To calculate the horsepower needed to accelerate a fixed assembly of a 40ft pipe and a 10ft x 10ft plate, which weighs a total of 8500 lb, the user initially computed the moment of inertia and torque. The calculations indicated a required torque of approximately 22,464.86 lb-ft²/sec² and a power requirement of about 0.30 hp to rotate the assembly 180 degrees in 10 seconds. However, confusion arose regarding the nature of acceleration and deceleration, with suggestions that the motion should involve constant acceleration for the first half and deceleration for the second half of the time interval. Clarification was sought on the correct approach to determine the necessary torque for the hydraulic motor to achieve this motion. The discussion emphasizes the need for accurate calculations to ensure the assembly can be effectively rotated.
ram18
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Hi,
I need to find out horsepower to accelerate pipe (40ft long) which is fixed with the plate (10ft x10Ft x 1inch) and whole assembly supported with bearing and shaft. I need to accelerate and decelerate this assembly 180 degree in 10 second ?

Plate weight = 4000 lb
pipe weight = 4500 lb
total weight = 8500lb.

bearing and shaft is perpendicular with respect to plate and pipe in the center

I done this calculation but its seems wrong can anybody tell me what i have to do for right solution . where i am wrong ?


Torque = moment of inertia x Angular acee

Power = Torque X angular velocity.

so i find out moment of inertia for plate and pipe .
Plate
Moment of inertia = mass X a X a / 6 = 4080 X 10x10 / 6 = 68000 lb-ft2.

Pipe ,

Moment of inertia = 647441.66 lb - ft2

Total M.O.I = 715441.66 lb - ft2.

i want to rotate this thing 180 degree in 10 second. so i consider 3 rpm .

angular velocity = 2pixn / 60 = 2x3.14 x3 / 60 = 0.314 rad/sec

angular aceen = change in velocity / time interval = 0.314 / 10 = 0.0314 rad / sec2.

avg angular velocity = 0.314 / 2 = 0.157 rad / sec

torque = total m.o.i x angular acee = 715441.66 x 0.0314 = 22464.86 lb-ft2 / sec2

power = torque x avg angular velocity = 22464.86 x avg angular velocity = 22464.86 x 0.157 = 3526.848 lb-ft2 / sec 3.

1 hp = 17696 lb- ft2 / sec3

so 0.30 hp required to rotate whole system in 10 second. it seems wrong. Can you guys give me some direction on that.

Thanks.
 
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hi ram18! :smile:
ram18 said:
I need to accelerate and decelerate this assembly 180 degree in 10 second

angular aceen = change in velocity / time interval = 0.314 / 10 = 0.0314 rad / sec2.

doesn't it mean that the angular speed will be zero every 10 seconds, with a constant acceleration for 5 seconds, and then a different constant acceleration for the next 5 seconds?
 
Actually i want to accelerate that assembly 180 degree in 10 second. I think all load is carrying by bearing so how can i calculate how much torque required to rotate this whole assembly. i m so confused now please give me some right direction.
 
ram18 said:
Actually i want to accelerate that assembly 180 degree in 10 second.

do you mean from 0° to 180° in 10 s, then from 180° back to 0° in the next 10 s, and so on? :confused:
 
Yes tiny tim can u help me on that .
 
ok, then that means that you need constant acceleration from 0° to 90° in 5 seconds, then an equal constant deceleration from 90° to 180° and back to 90° in 10 seconds, and so on …

how much is that acceleration? :smile:
 
Actually i want to rotate that system 180 degree in 10 second . can u tell me my above calculation is right or wrong for that please.

Thanks,
 
ram18 said:
Actually i want to rotate that system 180 degree in 10 second . can u tell me my above calculation is right or wrong for that please.

Thanks,

I don't understand …

what angular speeds do you want it to have at the angular displacements of 0° and 180° ? :confused:
 
i am going to use hydraulics motor to rotate that system 0 to 180 degree . And i want to know how much torque required to do that?
 
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