Calculating Torque: Window Washer Question

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Homework Help Overview

The problem involves calculating the tension in a rope supporting a scaffold with a window washer standing on it. The scenario includes the weights of both the scaffold and the washer, as well as their respective positions along the scaffold.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the torque equation, questioning the placement of the axis and the direction of torques. There is an attempt to clarify the contributions of the weights and the tension in the rope.

Discussion Status

Some participants have provided guidance on setting up the torque equation correctly, while others are exploring the implications of the torques acting in the same direction. Multiple interpretations of the setup are being examined.

Contextual Notes

Participants are working under the constraints of the problem statement and are questioning the assumptions made regarding the direction and effect of the forces involved.

kitty9035
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Homework Statement


A window washer is standing on a scaffold supported by a vertical rope at each end. The scaffold weighs 185 N and is 3.47 m long. What is the tension in the rope nearest the 747 N window washer when he stands 1 m from one end?


Homework Equations



sum of torques = zero
acceleration of gravity equals 9.8 m/s2

The Attempt at a Solution



I thought it was a simple problem but I get the answer wrong. My answer is 681.27 N. Is that right? If not how do i get the right answer??:eek:
 
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The first thing you need to do is to find an appropriate axis and put down all the torque effecting that point both clockwise and counterclockwise. Remember that the scaffold exerts its from the center of its mass.
 
I thought I did that. Is this the right set up?
0+185N(sin-90)(-1.735m) + 747N(sin-90)(-2.735)-3.47T=0
 
kitty9035 said:
I thought I did that. Is this the right set up?
0+185N(sin-90)(-1.735m) + 747N(sin-90)(-2.735)-3.47T=0
Here is your problem. Rewriting what you have written we have;

{\color{red}-}(185\times1.735){\color{red}-}(747\times2.735){\color{red}-}(3.47\times T)=0

This would mean that all the torques would tend to rotate the scaffold in the same direction, is the really what is happening?
 

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