Soaring Crane
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1) A wire, 7.0 m long with a mass of 50 g, is under tension. A traverse wave is propagated on the wire, for which the frequency is 160 Hz, the wavelength is .60 m, and the amplitude is 2.1 mm. The maximum transverse acceleration, of a point on the wire, in SI units is closest to:
a. 1600-------b.1300--c.1900-----d.2100------e.2400
Exactly what is the transverse acceleration in theory/formula? I know that partial derivatives are involved, but I don't understand how to use partial differentiation. Any hints for this problem are appreciated.
2) A wire, 2.0 m long, with mass of 40 g, is under tension. A transverse wave is propagated on the wire, for which the frequency is 330 Hz, wavelength is 0.50 m, and amplitude is 2.9 mm. The time, for a crest of the wave to travel the wire's length, in ms, is closest to:
a. 15------b. 12-----c. 16----d. 11----e. 14
v = sqrt(F_T/(m/L))
m = 0.04 kg
L = 2.0 m
F_T = 9.8 m/s^2*0.04 kg
v = sqrt[F_T/(0.04 kg/2.0 m)] = 4.4272 m/s
f = 4.27 m/s/0.50 m = 8.54 1/s
T = 1/8.54 s^-1 = 0.1172 s*(1000 ms/s) = 117.2 s
Now I am lost. How do I find the time for the crest with the amplitude and frequency?
Thanks.
a. 1600-------b.1300--c.1900-----d.2100------e.2400
Exactly what is the transverse acceleration in theory/formula? I know that partial derivatives are involved, but I don't understand how to use partial differentiation. Any hints for this problem are appreciated.
2) A wire, 2.0 m long, with mass of 40 g, is under tension. A transverse wave is propagated on the wire, for which the frequency is 330 Hz, wavelength is 0.50 m, and amplitude is 2.9 mm. The time, for a crest of the wave to travel the wire's length, in ms, is closest to:
a. 15------b. 12-----c. 16----d. 11----e. 14
v = sqrt(F_T/(m/L))
m = 0.04 kg
L = 2.0 m
F_T = 9.8 m/s^2*0.04 kg
v = sqrt[F_T/(0.04 kg/2.0 m)] = 4.4272 m/s
f = 4.27 m/s/0.50 m = 8.54 1/s
T = 1/8.54 s^-1 = 0.1172 s*(1000 ms/s) = 117.2 s
Now I am lost. How do I find the time for the crest with the amplitude and frequency?
Thanks.