Calculating Vapor Pressure Lowering for Glucose-Water Solution at 25oC

[amcavoy]

A solution contains 82.0 g of glucose (C₆H₁₂O₆) in 322 g water. Calculate the vapor pressure lowering at 25^oC. The vapor pressure of pure water at 25^o is 23.76 mmHg.

I calculated that there is 41/90 mol glucose and 92/3 mol water. Then I calculated the molar fraction of solvent in the solution, which I found to be .985. Next I multiplied the .985 by 23.76 mmHg and came up with 23.4 mmHg. To find the "lowering," I subtracted this from 23.76 coming up with a final answer of .348 mmHg.

Assuming I didn't make any arithmetic errors, is my process correct?

Thank you.

 

[Bystander]

Assuming I didn't make any arithmetic errors, is my process correct?

Yes. There is a math error in the calculation of the mole fraction.