Calculating velcoity around a corner

  • Thread starter Thread starter mistry
  • Start date Start date
AI Thread Summary
The discussion focuses on calculating the maximum velocity for a buggy navigating 90-degree corners in a mechatronics project. Key factors include the coefficient of dynamic friction, centripetal force, and the vehicle's mass. Users suggest using the formula F=mv^2/r to determine velocity, while clarifying that the coefficient of friction differs from rolling resistance. The conversation emphasizes the importance of understanding these principles to optimize speed and braking on the track. Overall, accurate calculations are essential for effective control of the buggy's movement around corners.
mistry
Messages
9
Reaction score
0
Calculating velocity around a corner

Hi Everyone,

I am working on a mecatronics project to control a buggy around a track, which uses sensors to determine where on the track it is and has a separate, rear wheel motor controls.

I want to perform a theoretical calculation to determine the maximum velocity I can go round the 90 degree corners? I know the distance around the corner, and the aim is to use this information to work out the time. Does anyone know how to calculate this?

The overall aim is by knowing tha max velcoity on the corners, I can work out speed on the straights knowing how much braking is requried.

Thanks in advance!

Mistry
 
Last edited:
Physics news on Phys.org
Hi Mistry,

First off I suggest read up a little about http://en.wikipedia.org/wiki/Circular_motion" , you will of course need to take into consideration a lot of factors about the vehicle such as the coefficient of dynamic friction between the tyres and your surface, air resistance and the centripetal force.

Hopefully this will give you a start for the logic.
 
Last edited by a moderator:
F=mv^2/r m=mass v=speed r= radius of the turn .
make sure this does not over come the frictional force by F=(mu)(N)
mu= friction coefficient , which is the tangent of the angle at which the material starts to slide on the other material , and N= the normal force (mass)(g)
 
Hi, thank you for your replies.

Could I clarify one thing. This coefficient of friction, is this the same a rolling resistance or is that completely different?

Also using the information given, I need to work out the maximum speed I can go round. If I take the coefficient of friction to be between 0.6-0.85 (for rubber tyres on concrete) can I state the follwing

m/V^2/r = (mu)N

then rearrange to find V. Would this be correct

Thanks
 
yes then you would solve for v , I’m not quite sure about the rolling resistance.
But I think rolling resistance is different than the friction coefficient because the friction coefficient refers to sliding not rolling.
 
Last edited:
comparing a flat solar panel of area 2π r² and a hemisphere of the same area, the hemispherical solar panel would only occupy the area π r² of while the flat panel would occupy an entire 2π r² of land. wouldn't the hemispherical version have the same area of panel exposed to the sun, occupy less land space and can therefore increase the number of panels one land can have fitted? this would increase the power output proportionally as well. when I searched it up I wasn't satisfied with...
Back
Top