Calculating Velocity Change for Hohmann Transfer Orbit

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To calculate the velocity change for a Hohmann transfer orbit from a circular low Earth orbit at 300 km altitude to an elliptical orbit with 300 km perigee and 3000 km apogee, the perigee and apogee distances from the Earth's center are determined as 6678 km and 9678 km, respectively. The velocity in the circular orbit is calculated using the formula √(μ/rp), while the angular momentum of the elliptical orbit is derived from the formula √{(2μ*rp*ra/(ra+rp)}. The velocity at perigee is then obtained by dividing the angular momentum by the perigee radius. The change in velocity (Δv) is found by subtracting the circular orbit velocity from the perigee velocity. The user seeks confirmation on the correctness of their formulas and values used, indicating a need for further guidance on solving the problem.
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Homework Statement



Consider an initial circular low Earth orbit act at a 300 km altitude, find the velocity change required to produce an elliptical orbit with a 300 km altitude at perigee and 3000 km altitude at apogee. Given gravitational parameter for Earth μ=398600 kg3/s2, radius of Earth R=6378 km.

The Attempt at a Solution



The perigee and apogee distance from center of Earth is
rp= 6378+300=6678 km
ra= 6378+3000=9678 km

velocity in circular orbit =√(μ/rp)

angular momentum (H) of elliptical orbit is=√{(2μ*rp*ra/(ra+rp)}

velocity at perigee = H/rp

change in velocity (Δv)= [H/rp]- [√(μ/rp)]
 
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And ... ?
 
I want to know the correct solution to the problem.
 
Well, you'll have to figure that out for yourself. As has been stated many times before, PF is not a homework service. If you provide an attempt at a solution, members will provide you with hints and feedback.
 
Oh sorry, may I know the relevant formulas used by me in the attempt are correct or not?? As I am not getting the correct ans by substituting values to those variables.
 
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