Calculating Velocity of Sliding Toolbox on a Slanted Roof

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SUMMARY

The discussion focuses on calculating the velocity of an 88.0 N toolbox sliding down a roof slanted at 44.0 degrees. The toolbox starts from rest and is subjected to a kinetic friction force of 21.0 N. The correct approach involves determining the net acceleration by accounting for gravitational and frictional forces. The final velocity can be calculated using the formula \( v = \sqrt{2a \cdot d} \), where \( d \) is the distance of 4.15 m.

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  • Calculate the net force acting on the toolbox using \( F_{net} = F_{gravity} - F_{friction} \)
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kgianqu2
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While a roofer is working on a roof that slants at 44.0 degrees above the horizontal, he accidentally nudges his 88.0 N toolbox, causing it to start sliding downward, starting from rest. If it starts 4.15 m from the lower edge of the roof, how fast will the toolbox be moving just as it reaches the edge of the roof if the kinetic friction force on it is 21.0 N?


To get the velocity I must do 2*a*4.15 (and then take the square root of the answer). I think the problem I am having is getting the correct acceleration. I have gotten 5.18 and 2.56. Both have gotten me nowhere. I really don't know what else to do, please help.
 
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Does this make sense?
 

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kgianqu2 said:
I have gotten 5.18 and 2.56.
Please show your working.
 

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