Calculating vertical displacement of an electron (millikan's experiment)

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To calculate the vertical displacement of an electron in an electric field, first determine the acceleration using the formula F = ma, where the force is the product of the electron's charge and the electric field strength. The horizontal speed of the electron remains constant at 8.7 x 10^6 m/s while it travels between the plates. The time it takes to travel the horizontal distance can be calculated using the plate length of 14.0 cm. Using the time and the vertical acceleration, the vertical displacement can be found by applying kinematic equations. This approach treats the motion as a projectile under constant vertical acceleration.
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this one question has got me confused...any help/hint would be appreciated.

an electron is traveling horizantally at a speed of 8.7*10^6 m/s enters an electric field of 1.32*10^3 N/C between two horizantal plates (shown below)
+ ___________________

e- ---->

- ___________________

The horizantal plates are each 14.0 cm and are distanced 8 cm from each other.

I need to calculate the vertical displacement of the electron as it travels between the plates.
 
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The electron is accelerated at a constant rate by the electric field. It's a simple matter to find its trajectory - mass times acceleration = charge times e-field.
 
if it helps, think of it as a regular projectile trajectory with the only force acting on the electron being vertical.The horizontal component of the speed stays the same, and it's accelerated towards the positively charged plate. the acceleration is given by Newton's second law according to Tide's post.
 
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